11x^2-42x-8=0

Solution for 11x^2-42x-8=0 equation:

11x^2-42x-8=0

a = 11; b = -42; c = -8;
Δ = b2-4ac
Δ = -422-4·11·(-8)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-46}{2*11}=\frac{-4}{22}
=-2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+46}{2*11}=\frac{88}{22}
=4
$